How (assuming you meant output rather than input)? Can you sketch the circuit arrangement you have in mind that would do this, or say what assumptions you are making about the supply internals?
Hi,
The circuit is simple, just two power supplies in series and those two also in series with a small "load" resistance, that is meant to draw current at 24v which here is the total series aiding voltage. In other words, connect two 12v supplies in series to make a single 24v supply, then connect a low value resistor across that 24v supply. Normally the resistor gets 24v.
However, turn only ONE of those supplies on first and leave the second one off, and we could see -12v across the second supply when it should be +12v. That is because there is now a low impedance path between the positive terminal of the upper supply and the negative terminal of the lower supply.
The circuit:
A o---12v---+---12v---+---RL---o B
and then connect A and B together to form a complete series circuit.
Next, turn only one on (lets say the top one) then we have:
A o---12v---+---open---+---RL---o B
and now assuming RL is small we see A connected to RL and RL connected to the (-) output of the second supply, meaning we end up with:
A o---(12v)---+---(-12v)---+---RL---o B
(again with A and B connected together).
The situation with a SPLIT supply (ground between the two to form plus and minus supplies) is not that much different unless BOTH loads are connected to ground and there is NO load that connects from the positive of one supply to the negative of the other supply (24v situation again).
For power supplies with an anti parallel diode, the reverse voltage may only be -0.7 to maybe -1.2v which probably isnt too bad although with some supplies it will blow out the diode and this defeat the purpose. A high current diode would keep it safe i think and should allow normal operation.