Yep. No path to discharge the base of Q2 in the original circuit without that 10K resistor.
Lots of circuits have nuances. ib of an OP amp can't drop across a wire. That caused me considerable grief.
Every circuit element has parasitic elements. In the real world you have to account for them.
In a certain Tektronix design, 3 resistors in parallel cannot be replaced with a single resistor. The inductances of the resistors mattered.
That's odd cause when I connect the circuit directly to the PLC it works just fine and that's how I ended up doing it but when I was using the SSR I had the current leak problem and considering that on a SSR the load is isolated from the input that problem seemed to me a strictly SSR output problem.
Interestingly after I put that resistor purely out of lack of knowledge I did a search to find why it worked and found the
following information which I've yet to understand. Not sure what power factor is
2.Reset Failure Using Load with Low Power Factor
If the power factor of the load is low (guideline: cosΦ=0.4 max.), the delay in the load current phase will increase relative to the load power supply voltage phase, and a large transient voltage (dv/dt) will be applied to the Solid-state Relay when it is about to turn OFF (i.e., the load current is near zero), resulting in the possibility of the Solid-state Relay not being able to turn OFF (commutation failure).
The Solid-state Relay has a built-in CR
snubber circuit to limit the rate of change in the transient voltage, but
leakage current will increase if the C value is increased, and reset failure in item 1 above may occur, so the C value is set to the greatest common factor.
Therefore, if reset failure occurs because the load power factor is low, the rate of change in the transient voltage can be limited to prevent reset failure by connecting a capacitor and resistor in parallel with the Solid-state Relay load terminals.
The capacitor and resistor must be checked to match the load, but previous experience shows that a resistor of 100 Ω/1 W and a capacitor of 0.1 μF/250 VAC will prevent reset failure.
Also, as mentioned above, the
leakage current will increase, so check that the reset failure in item 1 does not occur.