So followed the schematics from the 3.3v reg U716 back to K6R4008V1D pin 15 via resistor R368 rated 47k, reading in-circuit is 12.41kohm, urm well it is in-situ so could be right and its an smd so may have to chance lifting one end to measure. Interestingly pin 15 is labelled WE (Write Enable), this I.C connects to VCT49xyi (TV processor) so looks like I may be getting closer to the fault, perhaps. Now the question is, and I know that replacing the VCT49xyi is going to be beyond my abilities, but how do I determine what is at fault? Possibly the K6R4008 or the CVT49, would either of these being faulty correspond to the fault I am having???
What and how can either of these be checked?
I would doubt that the resistor had been damaged and suspect it will still be within spec's.
Updated : Resistor removed and checked and OK.
The K6R4008V1D has 3.3v on pins 11, 15 and 33 not that it means anything I guess.
Though really is 1v rise going to really damage something? OK, if it had risen to 6, 9 or 12v I would expect some damage. And most devices are resilient to a rise in voltage and operate at higher/lower voltages within reason.