Without a capacitor it will be 230V DC but very bumpy. The bumps will go from 0V to 230*1.414 - the peak voltage. With a capacitor, it will charge to the peak voltage - 230 * 1.414. The 1.414 is the square root of 2.
edit, the 0.707 you've encountered is one over root two and is how you convert the other way.
What would the frequency of the ripple, does it relate to the frequency of the AC current rectified so if it's 60HZ then the ripple will be at the same rate?
What would the frequency of the ripple, does it relate to the frequency of the AC current rectified so if it's 60HZ then the ripple will be at the same rate?
Here's a simulation to show the output from a full-wave rectified output for a 230Vac, 60Hz input (yellow trace).
Note that the output ripple is double the input frequency as Nigel noted, and that the average (DC) output is 204.75V and the RMS output is 227.4V (slightly less than I stated in post #4 due to the forward voltage drop loss of the diodes).