OK, i think THEONE this posted this diagrams a previous thread to help me out. However, i still dont really understand on how it works. REALLY SORRY ABOUT THAT(might be due to my lack of understanding on certain components). Anyhow, I dont intend to use this circuit, but its good to gain my knowledge on electronics principles.
TheONE stated this previously "Look at the 2 diagrams, the input Hi and Lo levels are generated by the switches in the diagram (I had to increase the cap values as I can't change over the switches that fast in the simulation to prevent some discharge of the caps) The PIC will of course do that at 10KHz .
OK, assume the input side of C1 is low (STEP1). C1 will now charge to (5v-1d) and C2 to (5v-2d) where d is the voltage drop over the diode. Now when the input of C1 is forced up to the +5v on the rising edge of the input (STEP 2), this now effectively places the -ve side of C1 on top of the 5v supply. Because the +ve side is now above the 5v line, D1 will now be reverse biased and a voltage of (C1v + 5v) will now be transferred to C2 through D2. The voltage will make the level on C2 to rise up to about 2 times the supply voltage. In this process C1 will discharge, ready for the cycle to repeat again. "
Can anyone please explain(especially THEONE), what are these switches? are they somekind of virtual switch or real switches? i can't see how they automatically on and off themselves.
THX VERY MUCH
(also dont mind telling me what simulation software is this? im need in need of a good one)