SinglePhotonGuy
New Member
Hi all,
I have a question regarding modifications to a "standard" plate-capacitor with plate area A, plate distance d and filled with a dielectric.
The equations for capacitance and electric field in this case are well known.
I found examples for what happens when inserting a thin conductor parallel to the plate, namely that it just "splits" the capacitor, resulting in two capacitors in a series with either reduced distance d1 and d2, depending where the conductor is inserted in relation to the plates. The respective capacitances can be calculated accordingly.
Is the inside of this conductor actually considered free of the eletric field of the capacitor in this case? Or does the electric field penetrate the inserted conductor? I remember something in the way of surface charges forming, which basically screen the inner part of the conductor? But I might also mix something up here.
The actual question to which this is leading up to:
What happens if I insert a thin slab of undoped semiconductor, let's say GaAs, into the capacitor, so that it is surrounded by the dielectric and is parallel to the plate? Can it be considered a dielectric, as long as the resulting field strength is not causing any charge carriers in the semiconductor to get into the valence band?
And would that mean, that the electric field of the capacitor is penetrating the semiconductor?
Thank you very much for your insights!
In general I would be interested if this could be a possibility to have an electric field in a semiconductor without having a p-i-n junction in reverse bias, which is often used to observe the (Quantum-Confined) Stark Effect.
I have a question regarding modifications to a "standard" plate-capacitor with plate area A, plate distance d and filled with a dielectric.
The equations for capacitance and electric field in this case are well known.
I found examples for what happens when inserting a thin conductor parallel to the plate, namely that it just "splits" the capacitor, resulting in two capacitors in a series with either reduced distance d1 and d2, depending where the conductor is inserted in relation to the plates. The respective capacitances can be calculated accordingly.
Is the inside of this conductor actually considered free of the eletric field of the capacitor in this case? Or does the electric field penetrate the inserted conductor? I remember something in the way of surface charges forming, which basically screen the inner part of the conductor? But I might also mix something up here.
The actual question to which this is leading up to:
What happens if I insert a thin slab of undoped semiconductor, let's say GaAs, into the capacitor, so that it is surrounded by the dielectric and is parallel to the plate? Can it be considered a dielectric, as long as the resulting field strength is not causing any charge carriers in the semiconductor to get into the valence band?
And would that mean, that the electric field of the capacitor is penetrating the semiconductor?
Thank you very much for your insights!
In general I would be interested if this could be a possibility to have an electric field in a semiconductor without having a p-i-n junction in reverse bias, which is often used to observe the (Quantum-Confined) Stark Effect.