For the toroidal cross sectional area i get A=d*H
where
d is the difference in outer and inner radii of the core and H is the height of the core.
Is that what you meant?
So for a core that has (in inches) outer diameter 3 and inner diameter 1, and core height 2 we would get:
d=3/2-1/2=1, and so
A=d*H=1*2=2 square inches.
A normal toroidal coil has a circular cross-section. So the core cross-sectional area is pi*r² or pi*d²/4 where r is the radius and d is the diameter (thickness) of the core.
Oh ok
I dont usually see toroids with round cross section though, i always see (and purchase) those with rectangular cross sections which are pretty common.
Oh ok
I dont usually see toroids with round cross section though, i always see (and purchase) those with rectangular cross sections which are pretty common.
Yeah you know it's funny because it's been so long since i heard anyone talk about a round cross section toroid that i totally forgot about those kind completely (ha ha).
It's good to remember them too though.