I have the following question regarding this circuit:
How is the opto being used to trigger the base of the triac?The collector of the photo-transistor is connected to the base of the triac. As per my understanding of npn transistors, the current flows from collector to emitter. But in this case the collector has no power source attached to it. So how would this photo transistor provide a signal pulse to the base of the triac?
That's where you problem stems from, I think that's entirely the wrong way to think about a circuit - current doesn't flow 'one way' (and thinking that way just confuses), and it certainly doesn't flow from collector to emitter, it just as easily flows from emitter to collector.
You also didn't specify what you meant by 'current' - for people who think about 'flow' you need to specify either 'conventional current flow' (+ve to -ve) or 'electron flow' (-ve to +ve).
As eric said, the drive 'flows' from D1, through T1, to the gate (not base) of the TRIAC - although you could just as correctly say it flows from the gate of the TRIAC, through T1, to D1.
I am talking about conventional current. I still don't get it.
Is it possible to have the flow (in the format you guys have given: from D1, through T1 to the gate) on a half-cycle of the AC wave, say when the lower terminal is at positive polarity.
And by negative power supply to the emitter, do you mean this transistor is being used in the emitter-follower configuration? If so , what could be the benefit behind it?
You also didn't specify what you meant by 'current' - for people who think about 'flow' you need to specify either 'conventional current flow' (+ve to -ve) or 'electron flow' (-ve to +ve).
I am talking about conventional current. I still don't get it.
Is it possible to have the flow (in the format you guys have given: from D1, through T1 to the gate) on a half-cycle of the AC wave, say when the lower terminal is at positive polarity.
And by negative power supply to the emitter, do you mean this transistor is being used in the emitter-follower configuration? If so , what could be the benefit behind it?
D1, D2, C1, C2 and R3 constitute a transformer-less PSU, giving around 14-15V DC across C1 - you could effectively ignore these components, and imagine C1 is a 15v battery.
The current from this 'battery' passes through T1 (which works as a switch), R2 (which limits the gate current - think of it as similar to the resistor you put in series with an LED), into the gate and back to the opposite end of the 'battery'.
The drive current doesn't pass through the load, it just turns the TRIAC on.
The photo-transistor just turns T1 ON, and while it's current will feed the gate as well, it's too small to be of any consequence.