C chesart1 New Member Nov 24, 2007 #1 Perhaps this is a good way to teach a student to think before diving into a solution to a problem.... what is the product of the binomials (x-a)(x-b)(x-c)(x-d)(x-e)(x-f)(x-g)(x-h)(x-i)(x-j)(x-k)......(x-y)(x-z) ??
Perhaps this is a good way to teach a student to think before diving into a solution to a problem.... what is the product of the binomials (x-a)(x-b)(x-c)(x-d)(x-e)(x-f)(x-g)(x-h)(x-i)(x-j)(x-k)......(x-y)(x-z) ??
erosennin New Member Nov 24, 2007 #2 welll... it would be x^26 + "don't know" + abcdefghijklmnopqrstuvwxyz I'll think about this don't know for a bit longer... lol
welll... it would be x^26 + "don't know" + abcdefghijklmnopqrstuvwxyz I'll think about this don't know for a bit longer... lol
C chesart1 New Member Nov 24, 2007 #3 [hint] I hope nobody tries to do the multiplication. If they do, they are going to be really angry when they find the answer! LOL
[hint] I hope nobody tries to do the multiplication. If they do, they are going to be really angry when they find the answer! LOL
C chesart1 New Member Nov 24, 2007 #4 erosennin said: welll... it would be x^26 + "don't know" + abcdefghijklmnopqrstuvwxyz I'll think about this don't know for a bit longer... lol Click to expand... Sorry! Thats not the answer.
erosennin said: welll... it would be x^26 + "don't know" + abcdefghijklmnopqrstuvwxyz I'll think about this don't know for a bit longer... lol Click to expand... Sorry! Thats not the answer.
erosennin New Member Nov 24, 2007 #5 OHHHH I GET IT!!!!! once you get to (x-x) !!!! excelllent!!!! FANTASTIC
ParkingLotLust Member Nov 25, 2007 #6 What's the answer, out of curiosity? EDIT Clever, now that I think about it. Zero, since (x-x) = 0, which nulls everything else. Last edited: Nov 25, 2007
What's the answer, out of curiosity? EDIT Clever, now that I think about it. Zero, since (x-x) = 0, which nulls everything else.
V vicky877 New Member Nov 27, 2007 #7 Is this rule true or not ? (x)^0=1 if it is true then justify..
S Salgat New Member Dec 2, 2007 #10 One of the multiples is (x-x), zero multiplied by the whole thing results in zero.
erosennin New Member Dec 2, 2007 #11 vicky877 said: Is this rule true or not ? (x)^0=1 if it is true then justify.. Click to expand... x^0 = x^n/x^n = x^(n-n) = 1
vicky877 said: Is this rule true or not ? (x)^0=1 if it is true then justify.. Click to expand... x^0 = x^n/x^n = x^(n-n) = 1
RODALCO Well-Known Member Dec 2, 2007 #12 0 or ZERO ! is the total. Anything multiplied by zero = zero.
Nigel Goodwin Super Moderator Most Helpful Member Dec 3, 2007 #13 RODALCO said: 0 or ZERO ! is the total. Anything multiplied by zero = zero. Click to expand... You don't do 'further maths' do you?, apparently it can be any value at all? - and I don't understand it either - but my daughter (doing A level further maths) does!
RODALCO said: 0 or ZERO ! is the total. Anything multiplied by zero = zero. Click to expand... You don't do 'further maths' do you?, apparently it can be any value at all? - and I don't understand it either - but my daughter (doing A level further maths) does!