Trying to learn about devices but fail.
Hey,
I always find myself fails in understanding about how devices work and I dont know why it happens all the time.
For example, I decided to understand how probes work, and read in Wikipedia that in 10x probes, there's a 9Mohm resistor that is connected in series with the probe tip in order to decrease the loading that the cable capacitance would impose on the DUT (Device Under Test).
How can resistance decrease capacitance?
I might be just a student who finished only two years in EE but we're never taught that resistance can decrease capacitance.
This kind of things always stop me from learning about devices that I use in the everyday without knowing how they work.![Frown :( :(](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
--
After reading more I have 2 question please:
1. The 9Mohm resistor is said to decrease the loading capacitance because it requires a parallel capacitor to reach 10x attenuation also for AC signals?
Meaning its the parallel capcitor which decreases the loading capacitance?
2. How do they choose that parallel capacitance to reach constant 10x attentuation for all frequencies?
Thanks.
Hey,
I always find myself fails in understanding about how devices work and I dont know why it happens all the time.
For example, I decided to understand how probes work, and read in Wikipedia that in 10x probes, there's a 9Mohm resistor that is connected in series with the probe tip in order to decrease the loading that the cable capacitance would impose on the DUT (Device Under Test).
How can resistance decrease capacitance?
I might be just a student who finished only two years in EE but we're never taught that resistance can decrease capacitance.
This kind of things always stop me from learning about devices that I use in the everyday without knowing how they work.
--
After reading more I have 2 question please:
1. The 9Mohm resistor is said to decrease the loading capacitance because it requires a parallel capacitor to reach 10x attenuation also for AC signals?
Meaning its the parallel capcitor which decreases the loading capacitance?
2. How do they choose that parallel capacitance to reach constant 10x attentuation for all frequencies?
Thanks.
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