Why are you talking about speakers?, there's no mention of driving a speaker in the question at all.
The question IMO is moot, based on (I think) a misunderstood point I made to do with driving the speaker.
We'd been talking about driving speakers for the last 9 or so postings.
I specifically asked in #36: "isn't the 50 ohm resistor the actual speaker being directly driven?" and this question was
not answered. Therefore, logically there is instead a AC-coupled 50 ohm speaker placed across this resistor, the way I saw it anyway, maybe I'm getting too far ahead.
I said: "You double the output power by having this DC going through the speaker instead of a resistor." Which appears to had been misunderstood. Serves me right for being ambiguous.
I'll try and use more words in the hope it can be understood. Presently, there is DC current going through the 50 ohm resistor. Not shown on the schematic is the actual speaker, via a blocking capacitor (which was not denied when I asked about it). Therefore I am saying that in a practical circuit, the 50 ohm resistor be removed completely, and the speaker be substituted for this resistor. Or in other words, remove the 50 ohm resistor, and make this the speaker instead, with DC bias through it. Or another way of putting it, substitute the 50 resistor with a 50 speaker, directly driving it, instead of a resistor as well.
Because if it is not, a 50 resistor shunts the 50 speaker. I think this one is obvious, so I won't elaborate any more