Yes.
Within the confines of the zener's specifications, what you suggest is valid.
New test:
8V = 4.52V / 53.61mA
10V = 4.92V / 78.11mA
12V = 5.13V / 105.62mA
18V = 5.46V / 192.98mA
24V = 5.63 / 282.58mA
even pushing it to 100V is only 6.42V, that seems sensible & when were talking mA, this is minute really isn't it = 1.44A off 100V
One of the problems with using a zener as a voltage controller is that at the higher current ratings
it takes a greater minimum current through the zener to get it into "steady" or specified VDC output mode.
As the load draws additional current away from the zener, the available current for the zener to maintain its "steady state" output voltage is reduced, eventually to the point of no longer working as specified.
That's why a voltage regulator chip, like what you spec'ed out at the beginning, is a better choice for your needs. It can handle the additional current requirements of the load without losing the ability to maintain the appropriate voltage level(s).
failing the zener being the right product, is it possible to make one,
so what your saying is it takes 0.5A to keep the zener in the reverse state
so what happens when you take the load out & it pushes the voltage above the normal working threshold
so this zener could work between 4.84-5.35V, those are the min/max with PRV of 890mA, when I was looking at 2000mA draw, so this still couldn't do what I wanted without a transistor
tbut the Zener is more of a part of a control rather than a single component solution
Can't believe how much electronic parts costs you guys. Wow.
So, no. Unless you want to really beat yourself up.
No. For the 1N4733, minimum reverse current is 49mA (0.049mA), although there is some slop around that value. As you can see, in my sim the zener holds 5.08VDC with 46.12 mA flowing through it. (EDIT: Ref post #302)
With no load (open circuit) the internal resistance of the zener rises (thereby reducing the current flow) to a level that corresponds to the resistance needed to maintain 5.1VDC. In the 12VDC supply voltage example, Z1C (and the current thru R1 as well) goes to 67.9mA, with a 5.21VDC value across the zener (and the remainder of the 12VDC, 6.79VDC across R1). This is the minimum current flow the system will draw with 100 Ohm current limiting resistor (R1) in series with it (as per the example schematics). This is the so called quiescent state, i.e., what the circuit draws with No load.
Well, Yes and no, but again, I think your misunderstanding the reason for using a zener vs. a voltage regulator "chip" such as the LM317 or any of the LM sereis (maybe not ALL).
Yes, in the present context. And Yes again. Nail that thought down.
A zener is designed to be primarily a voltage regulator: It is not "supplying" current to a load so much as "diverting" it so as to maintain the desired voltage across the load.
A device such as the LM317 maintains not only a constant voltage but also supplies a variable current depending on the requirements of the load(s). It is, as you can see, a pretty sophisticated device and it takes that level of sophistication to achieve this process.
In a word, you would not ordinarily substitute a zener for the job of a voltage/current regulating device.
Did I cover everything?
The zener is a SHUNT voltage regulator. The controlling element (The zener itself) is in parallel with the load. Regulators like the LM317 is a SERIES regulator where the controlling element (transistor(s), FET(s)) are in series with the load.
With power supplies, there are usually a couple of specs. Line regulation and load regulation. Line regulation is how the output changes with input voltage changes and load regulation is how the output changes with load changes.
ok, need to go back to sim for that one to make sure I fully understand it, can see where your putting your meters so I can relate it to process I used to try & understand **broken link removed** big miss on my part there **broken link removed**
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