Hello again Brownout,
Of course this could have been also been clear when i said "Ok, i thought you said you thought that charge flows through a capacitor".
What "displacement current" is from a physical standpoint, is the time rate of change of the electric flux.
Don't most of the standard methods of measuring "conduction current" rely on the effects of fields produced by the flow of the charge carriers? Otherwise, wouldn't we have to utilize some way of actually counting the carriers go by?
Thanks kilo, that was fascinating. I don't think I'll try to do it though.And for you amusement, this is how is was done or so to speak.
Hand Making a Vacuum Tube Part 1
Hand Making a Vacuum Tube Part 2
We sort of have a couple different arguments going here, i think that is part of the problem. We are
arguing about:
1. What this 'displacement current' really is.
2. If it really can be called a 'current' at all.
For #1, it appears that what is being called a displacement 'current' is actually just a change in a
field flux, but multiplying that change by the permittivity of free space puts it in units of Amperes.
Thus, this leads people to call it a 'current'.
The other side says that the change in field flux only creates a B field, and that the displacement current
is not a real current by any scope of the word.
For #2, it's almost the same as #1, because before we know what to call it we have to know what it really is.
It has been traditionally called the 'displacement current', because it works out to units of Amperes. But
we know that amps is a flow of charge carriers. So the question becomes: is it really a flow of charge
carriers or not? If we want to say that it is we'd have to figure out how it can get through the
vacuum of space. ...
Thanks kilo, that was fascinating. I don't think I'll try to do it though.
You would need a lot of skill, knowledge & equipment.
Just add SAVE or KICK after www in the address of the youtube video;
h ttp://saveyoutube.com/watch?v=dXP2GdqYCOM
h ttp://kickyoutube.com/watch?v=dXP2GdqYCOM
Then you can select the format to save the video in. These facilities are provided outside of youtube's control so use at your own risk.
I was just curious about the Vacuum tube construction. I thought obtaining a complete Vacuum is difficult if not impossible. I thought it would be good to understand Vacuum tube construction in order to know what was really happening. Now, I see it is reasonably easy once you have removed most of the air heating the glass would then boil anything remaining in the bulb I would assume. I thought how was it done, in Maxwells day.
For anyone interested in Vacuum tube construction. Apparently they air still making them in America I thought that was a bygone and would only be available in other country's.
Vacuum tube - Wikipedia, the free encyclopedia
Hi again,
Well Mr RB let me put something else in your field of view here. This is interesting i assure you
We have two tanks of water, first one on the left, second one on the right. They both have 100 gallons of water in them when we start and nothing is moving.
We also have a pipe coming from the second tank going to a pump (which is not running), and the pump connected to another pipe that goes to the first tank.
Now we turn on the pump and pump water into the first tank so water flows through the two pipes and pump, but because of the piping we can only get that water from the second tank. This means that as the first tank gets more and more water, the second tank looses more and more water. Note that we did not have any other connection between the two tanks as they are separated from each other.
Question 1: We only have one pipe connected to each tank, so where is the displacement current? See below.
Question 2: Assuming a flow rate of 1 gallon per second, how much water is pumped into the first tank after 1 second?
I don't know if vacuum pumps were available in those days, but I think they were.But, the getter may have not been available at the time of Maxwell. I actually was hoping someone would comment on it since I didn't know. Plus if you are using a getter it would only apply to Diodes & Triodes & Pentodes when I read the wiki article, it said, to stabilize performance over time because of the high heat generated from the heater, maintaining a thermal equilibrium & vacuum.
In the instance of the Capacitor this would not apply. It does not require a heater. Only a complete vacuum without assistance from artificial methods to dry them. You wouldn't want to use RF to stimulate the A - B plate either in order to raise the temp forcing any remaining molecules. This process might also produce carbon which might influence the Chamber as well, De-stablizing the performance & altering the characteristics of the Capacitor or so you would think!
Maybe someone could explain more for me as I just don't understand. A bit confusing.
But, again I just don't understand how it was constructed back then, either.
Hi again,
Question 1: We only have one pipe connected to each tank, so where is the displacement current?
Question 2: Assuming a flow rate of 1 gallon per second, how much water is pumped into the first tank after 1 second?
But, the getter may have not been available at the time of Maxwell. I actually was hoping someone would comment on it since I didn't know. Plus if you are using a getter it would only apply to Diodes & Triodes & Pentodes when I read the wiki article, it said, to stabilize performance over time because of the high heat generated from the heater, maintaining a thermal equilibrium & vacuum.
In the instance of the Capacitor this would not apply. It does not require a heater. Only a complete vacuum without assistance from artificial methods to dry them.
There is no displacement current, because this has nothing at all to do with electro-magnetics. Displacement current is valid only for electro magnetic phenomona.Ask a plumber.
Jon Wilder said:It is this charging/discharging action of the cap that becomes the AC on the other side, while the static DC on the DC side of the cap is blocked.
The "displacement current" is the air that flows out of one tank & into the other.
However, this is not a valid argument with or without the "displacement current" as it is a completely different situation to that inside a capacitor
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