Thanks again.
1. The component values. I am not sure if they are suited to my 9 or 10 AMP requirement, but they are as close as I could figure from what I know at this point. Voltage must be adjustable between the minimum-possible(3?) and 18 or 20 or whatever is best for the circuit?
2. I need to know how to decide on a base driver tran, Q1.
3. Instead of two 2N3055's, if I use two higher rated transistors, the heat dissipated will still be the same, but the transistors will be more "OK" with it, am I correct? I Have decided on 2N5038's for the pass's
4. Lastly, I have a 0-30V analog meter, and a 0-15A analog meter, can I just hook them up as usual? V in parallel and A in series with output?
Will this work or quirk?
Disclaimer: I've only looked at this for a few minutes, so my comments do not reflect an exhaustive review.
1. Seems like the resistor values around the LM723 are OK. I'm very uncomfortable with your 4700 uF cap as that strikes me as kind of puny for a 10amp supply. On the other hand, your peak voltage at the cap will be around 33 Volts, and since you are only taking up to about 20V after the regulator, that means you can tolerate 10 volts pp of ripple at the input to the regulator, so maybe the cap value is adequate.
2. To figure this one out, work back from the output. You will take 10 amps at the output. Q2 and Q3 theoretically must deliver 5 amps each, and each is specified to give a minimum current gain of 20 (approximation from data sheet info), so each base must receive 5/20 or 250mA. Q1 has to deliver about 0.5 amps. Since the 723 can only deliver around 150 mA, the gain of the driver must be at least .5/.15 or 3.3. Seems easy, but then this is all in theory. In practice, you need extra gain to deal with transients and surge current. So Q1 needs to give you some gain but must be comfortable operating with at least 0.5 amps of collector current (double that to be conservative). The next thing is that you have to deal with a lot of heat here. The collector voltage on Q2 and Q3 will be about 32 volts, while the emitter voltage will adjust from 3 to 20. If we assume that you have adjusted it down to 3V and you want 10 amps out of this, then the power that those two transistors have to blow off as heat is (32-3) x 10 = 290 watts. Theoretically this is shared by the two transistors. Thats a lot of heat, so I suggest a big heatsink plus a fan blowing directly on the heatsink. I keep saying theoretically because I have seen most designers add some additional resistors to help balance the work done by the two pass transistors. As it is right now, one might deliver more current than the other simply because they are not identical (or as we say "matched"). If one delivers more current, then it will generate more heat. More heat causes bipolar transistors to lose gain and increase Vce, which causes even more heat. At some point, such transistors suffer thermal runaway and they burn out. So, balancing the work between them is a good thing. Trouble is, I'm not an expert in that area, so we need other posters to chime in on how to do that.
3. yes. your choice seems ok
4. yes, hook them up as you say, they should be fine.