hi there audio guru,
Thanx for the information on the inductor...based on your diagram, you have 9 turns of a 1mm wire right? so the following can be calculated :
1mm=0.0393700787402 inches
3mm=0.1181102362206 inches
length of coil=0.4 inches (to be exact 9 turns X 1mm = 9mm)
9mm=0.3543307086618 inches
using the formula:
L= (d^2 * n^2)/(18d+40l)
where:
L is inductance in micro Henrys,
d is coil diameter in inches,
l is coil length in inches, and
n is number of turns.
then the inductance of the coil would be=0.06933uH
This value deviates from the 0.1uH of your original circuit. Would this affect anything?
on the other hand, you mentioned that the resistance is too high and the self resonance is too close, what about this one?we basically try and avoid self resonance as the impedance would be very high at resonance right?
what about this one with 0.26 ohm dc resistance and 1310MHz resonant frequency:
EPCOS|B82498B3101J|INDUCTOR, 0805 CASE, 100NH | element14 Malaysia
thanx in advance for the great help!