but ohms law says i = v / r which would be
5.18v / 1.2K (1200) = 0.0041mA
Which should be 4mA why do i read 2.7mA ?
EDIT:
I see without the led its 4.3mA. How would i account for led?
And when i add led why is it showing less current?
Hi,
Whats the voltage drop across the LED.?
You have to subtract that voltage from the Vcc in order to calculate the current in the circuit.
(5.18v-Vled) / 1.2K (1200) = 0.0027
example:
(5.18-1.6)/1200 = 0.0029A
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