bananasiong
New Member
Hi,
I've done tested this boost regulator IC according to the datasheet.
https://www.linear.com/pc/productDetail.jsp?navId=H0,C1,C1003,C1042,C1031,C1060,P1897
**broken link removed**
but I just modified the output voltage to be almost 5 V by changing the resistor value, so that I can use it for my LCD display. With no load, the output is almost 5 V. When the battery is fully charged, it can power up the LCD and a PIC for hours (I'm not sure how long, just leave it there, maybe just 1 hour). When the battery drops to 1 V, it lasts for only a few second
Maybe the design is for 3.3 V output only.
I've measure the current drawn by the LCD and the PIC, it is not more than 2.5 mA. Just wonder is there any way to improve the running time?
BTW, I'm using a sony rechargeable battery, 2500 mAh.
**broken link removed**
I've done tested this boost regulator IC according to the datasheet.
https://www.linear.com/pc/productDetail.jsp?navId=H0,C1,C1003,C1042,C1031,C1060,P1897
**broken link removed**
but I just modified the output voltage to be almost 5 V by changing the resistor value, so that I can use it for my LCD display. With no load, the output is almost 5 V. When the battery is fully charged, it can power up the LCD and a PIC for hours (I'm not sure how long, just leave it there, maybe just 1 hour). When the battery drops to 1 V, it lasts for only a few second
Maybe the design is for 3.3 V output only.
I've measure the current drawn by the LCD and the PIC, it is not more than 2.5 mA. Just wonder is there any way to improve the running time?
BTW, I'm using a sony rechargeable battery, 2500 mAh.
**broken link removed**