Buzzer/Speaker...What's the diff?

[3v0]

I am using ringtones. The speaker is on more the off.

EDIT: This sort of thing.

#ifdef AdamsFamily   
    /* AdamsFamily */
    rom const unsigned char static Melody[] =  
    {"8c1,4f1,8a1,4f1,8c1,4b4,2g1,8f1,4e1,8g1,4e1,8e4,4a4,2f1,8c1,4f1,8a1,4f1,8c1,4b4,2g1,8f1,4e1,8c1,4d1,8e1,1f1,8c1,8d1,8e1,8f1,1-,8d1,8e1,8#f1,8g1,1-,8d1,8e1,8#f1,8g1,4-,8d1,8e1,8#f1,8g1,4-,8c1,8d1,8e1,8f1"};
    defaultoctave = 6;
    defaultduration = 4;
    beat_speed = 160;
#endif

 

[Hero999]

That's expensive.
**broken link removed**

 

[saturn1bguy]

It's a VERY comon technique called 'bridging',

DOH!

Yes, I knew there was something familiar about what you folks were describing, but I couldn't put my finger on it. Sometimes a gentle reminder is all we need

 

[Urahara]

Does anybody know if the buzzer can produce a sound like this? Hv tried a few combo but still unable to get it. Otherwise, I will look for other types of buzzer/speaker to try it out. Thks!

https://www.metronomeonline.com/

 

[Sceadwian]

How exactly does bridging on a piezo element work? The outputs aren't isolated so at no point does the UC itself provide 10V P-P, the only thing I can think is that the piezo capacitance itself acts as the final required part of a switched voltage doubler? If that's the case wouldn't the effective capacitance of the element lead to a second harmonic trait? The first being the natural harmonic of the crystal and the second being a combination of the effective capacitance and the impedance at the driven frequency? Doesn't that give a VERY non linear frequency response?

 

[Nigel Goodwin]

How exactly does bridging on a piezo element work? The outputs aren't isolated so at no point does the UC itself provide 10V P-P, the only thing I can think is that the piezo capacitance itself acts as the final required part of a switched voltage doubler? If that's the case wouldn't the effective capacitance of the element lead to a second harmonic trait? The first being the natural harmonic of the crystal and the second being a combination of the effective capacitance and the impedance at the driven frequency? Doesn't that give a VERY non linear frequency response?

You need to study how bridging works, outputs don't need to be isolated, and probably wouldn't work if they were.

It's nothing to do with a piezo, it applies equally to any load.

Bridging a PIC like this provides 10V p-p, just as any bridged circuit effectively doubles the supply voltage.

 

[ericgibbs]

It's nothing to do with a piezo, it applies equally to any load.

Bridging a PIC like this provides 10V p-p, just as any bridged circuit effectively doubles the supply voltage.

hi Sceadwian.

An analogy would be, if you had a loudspeaker, applied a 1.5Vdc battery voltage to the terminals, the cone would always move the same way the same distance.

If you now reversed the battery the cone would move the opposite way for the same distance.

If the battery connection was reversed fast enough the cone would move double the distance, its a push pull action.

 

[Sceadwian]

I always over look the mechanical =O

 

[mudassir_semiconductor]

IF you just want to make a sound like PC, make a mono stable 555 timer circuit which gives ur the freq with respect to pot ....... add pc spk ( motherboard small spk) to the output of 555 timer u will get beep sounds...