I am using a one ounce per square foot printed circuit board single sided. High frequency is not an issue.
At 5 volts DC and a max of 0.2 amps, I set about trying to calculate the trace width that would be needed.
Attempting to use this calculator
https://www.circuitcalculator.com/wordpress/2006/01/31/pcb-trace-width-calculator/
I came up with 1.28 mils.
Doing the math of 5 times 0.2 , I come up with 1 watt max for the trace.
I think a hair is thicker than 1.28 mils and this is going to carry a watt of power. The calculator has no entry line for volts. What if the voltage was 500. We now have 100 watts of power. Will the trace width still be 1.28 mils?
Calculating the wire size needed and then applying that to the trace width seems a far better way to do this?
Can anyone give me a method that makes sense to me?
At 5 volts DC and a max of 0.2 amps, I set about trying to calculate the trace width that would be needed.
Attempting to use this calculator
https://www.circuitcalculator.com/wordpress/2006/01/31/pcb-trace-width-calculator/
I came up with 1.28 mils.
Doing the math of 5 times 0.2 , I come up with 1 watt max for the trace.
I think a hair is thicker than 1.28 mils and this is going to carry a watt of power. The calculator has no entry line for volts. What if the voltage was 500. We now have 100 watts of power. Will the trace width still be 1.28 mils?
Calculating the wire size needed and then applying that to the trace width seems a far better way to do this?
Can anyone give me a method that makes sense to me?