The current gradually dies to 15mA.
We are not switching off the inducutor. The current drops to 15mA.
And secondly the energy produced (if the inductor is switched off) is determined by the voltage and current flowing though the inductor. These values are very small and so any back energy will be very small.
It's not even a value worth considering.
On top of this you have two diodes that will clip any back voltage so I don't know why you even brought up the point.
We are not switching off the inducutor. The current drops to 15mA.
And secondly the energy produced (if the inductor is switched off) is determined by the voltage and current flowing though the inductor. These values are very small and so any back energy will be very small.
It's not even a value worth considering.
On top of this you have two diodes that will clip any back voltage so I don't know why you even brought up the point.
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