Baske7Cas3
New Member
Ok well im new to this site and to electronics but I would love to be a part of both so try not to be to mean when I ask this question lol, even though it is a extreme beginner question im guessing.
Ok well I have a capacitor set up like in the link below. This link is the only thing I have that can help explain so here it is. I am also going to try to write it out in words.
https://www.howstuffworks.com/framed.htm?parent=capacitor.htm&url=https://micro.magnet.fsu.edu/electromag/java/capacitor/
Below is the description of how it is set up but I want you to know first that it is set up just like that picture in the link but I have an LED where they have nothing hooked up. (where the charge out of the capacitor flows)
I have a switch with a toggle on/off(open)/on. On one of the "On's" I have a 9volt battery hooked up with the positive connection to the switch and when it comes back around to the "Open" I have a capacitor hooked up to the switch so the battery power runs through the switch and charges the capacitor. On the same side that the battery is connected to the capacitor, I also have another wire running out of the capacitor which then attaches to and LED and which in turn goes into the other "On" part of the switch.
So, I flip the switch to the first "On" and it charges the capacitor and then I flip it to "Off/Open" and then I flip it to the next "On" which releases the energy from the capacitor and runs through the LED which lights it up and then I think but im not sure that it comes back around into the capacitor to cancel itself out or something...Like I said im new. I know I should learn the basics first but I want to get this solved first then I will learn the basics.
Ok well now that you know my set up I can ask the question, this may sound like a retarded one and it pretty much is, but I am wondering as to why when I take out the LED and just hold onto wires that connect back around from the switch to the capacitor that I do not get shocked. I realize that current is running through the LED which makes it light up so why dont I get shocked or feel anything when I hold onto the wires that the current passes through.
I am very sorry for that sorry explanation of a schematic/set-up. If you would like me to clarify on a certain part of it please post a comment and I will do so ASAP.
Ok well I have a capacitor set up like in the link below. This link is the only thing I have that can help explain so here it is. I am also going to try to write it out in words.
https://www.howstuffworks.com/framed.htm?parent=capacitor.htm&url=https://micro.magnet.fsu.edu/electromag/java/capacitor/
Below is the description of how it is set up but I want you to know first that it is set up just like that picture in the link but I have an LED where they have nothing hooked up. (where the charge out of the capacitor flows)
I have a switch with a toggle on/off(open)/on. On one of the "On's" I have a 9volt battery hooked up with the positive connection to the switch and when it comes back around to the "Open" I have a capacitor hooked up to the switch so the battery power runs through the switch and charges the capacitor. On the same side that the battery is connected to the capacitor, I also have another wire running out of the capacitor which then attaches to and LED and which in turn goes into the other "On" part of the switch.
So, I flip the switch to the first "On" and it charges the capacitor and then I flip it to "Off/Open" and then I flip it to the next "On" which releases the energy from the capacitor and runs through the LED which lights it up and then I think but im not sure that it comes back around into the capacitor to cancel itself out or something...Like I said im new. I know I should learn the basics first but I want to get this solved first then I will learn the basics.
Ok well now that you know my set up I can ask the question, this may sound like a retarded one and it pretty much is, but I am wondering as to why when I take out the LED and just hold onto wires that connect back around from the switch to the capacitor that I do not get shocked. I realize that current is running through the LED which makes it light up so why dont I get shocked or feel anything when I hold onto the wires that the current passes through.
I am very sorry for that sorry explanation of a schematic/set-up. If you would like me to clarify on a certain part of it please post a comment and I will do so ASAP.