Rookie question...
One more question, and it's probably a kindegarden-level question...but I'm still learning so here goes:
Do the 1M+100K resisters effectively act as enough of an "open" to prevent the 1M+100K resisters from completeing a circuit back to the battery, and draining the battery?
I understand the 10K+microphone loop is going to drain current, but won't the loop that consists of the 1M and the 100K also drain some current?
Or is that such a high resistance that it almost acts as an "open"? And if it does almost act as an "open" for that reason...what do you need that circuit path for? Why not just remove the 1M/circuit path completely?
In Caster's circuit (that worked but may drain battery?) that same area adds up to 43.7K...so even less...
Or is my math/understanding wrong on 1M+100K total resistance through the 1M circuit path?
I think I understand the circuit, except for THAT loop...
And, will the battery see the 10K being in parallel with the 1M, cause the 1M+100K path to be even less?
What is the resistance in the red loop, or can it even be looked at that way?
**broken link removed**
In other words, what exactly is that 1M/circuit path there for? Do you even need that circuit path, or can everything on the BASE side of Transister1 go through the 10K/blue loop? Why not take the 1M resister out completely?