Optikon said:
Ron H said:
Those inductors you have drawn are really transmission lines, and they will resonate and cause your transistor to oscillate. Try putting the resistor in series with the other end of the cable (the +8 volt end). This is counter-intuitive, but it should terminate the cable in something near its characteristic impedance, reducing reflections and hence ringing/oscillation. Putting the resistor near the collector will dampen the resonance, but it is a poor termination.
I think the original author has his problem under control now but I'd like to hear some elaboration on this point. I feel like you are talking about source termination of his "wire" transmission line in this case. My undersanding is that if you have a mismatch at the load, you will get at least one reflection. As you suggest, source terminating will stop that reflection and prevent a second one from occuring. But in general, the only way to eliminate any reflections is both source and load termination.
1) Source and load terminated (BEST)
2) Source mismatched, but load terminated (Better)
3) Source terminated, but load mismatched (Better)
Between choices 2 and 3, which is better? and why?
The collector is the (current) source. The 8 volt battery looks like a short circuit at the load end. If you have a line which is shorted at the far end, the short will cause 100% reflection. If the source is an open circuit (current source, as we have here), then the wave reflected from the short will reflect again. Not a good thing unless you want to generate ringing. The resistor I suggested adding would be a load termination.
If you have a tline with no parasitics (L and/or C) at the load end, then a perfect load termination (R=Z0) will not generate a reflection, so source termination is not necessary, regardless of the impedance of the source. The only effect of a source termination would be 50% signal amplitude at the load. If you need to place taps (receivers) at intermediate points on the line, source and load termination is necessary.
If you have a tline with no parasitics (L and/or C) at the load end, the absence of a load termination will cause 100% reflection,but a perfectly matched source termination will absorb the reflection completely, so the waveform at the load will still be perfect. Intermediate points will still look bad, because the reflected wave interferes with the incident wave.
If you have a line with source parasitics, but no load parasitics (as we have in my suggestion), then load termination will still not generate any reflection.
Having said all that, nearly all practical applications have parasitics on both ends, I think that, if you need to preserve signal amplitude, load termination is generally preferable to source termination for signal integrity, partly because proper source termination must include the impedance of the driver, which frequently is nonlinear and varies from device to device. Receivers, on the other hand, generally have input impedance much higher than the transmission line (which will never be more than about 120 ohms), and so are easier to terminate. One disadvantage of load termination is that it dissipates more power than source termination. As you said, for best signal integrity, source
andload termination is best.