Hi,
I am trying to use the Reset Pin of NE555 to give it a switch off and delayed start but failed as the 555 requires just above 0.7v on the reset pin to become on again.I had connected pin 4 to plus via a resistor and capacitor at pin 4 to ground.I need to create a short circuit protection for my circuit using 555 to drive an inductive load through a transistor.When current exceeds 0.6A across the R1 or R3 the transistor Q1 or Q2 conducts and brings Point A or B to Vcc or ground.I need instant shutdown off 555 and a delayed start back.I have a spare opamp that can be used if needed.Either of The circuit consisting of R1,R2,R5 and Q1 or R3,R4,R6 and Q2 can be used.
Your sim has R4 connected to ground, so Q2 stays off and there is nothing to reset the 555 after the initial power-up reset. Did you try the sim I posted?
Here's a revision of your circuit, with overcurrent simulated by turning on Q2 with V2 :
"Did you try the sim I posted?" Yes I did try but for that I would have to add another IC in my board.I had already designed my board thinking that the 555 would reset below 1/2 Vcc so a standard RC delay would do the work.My only help is using the spare opamp.What is V2? My only sensing is the voltage drop across R3 that would develop 0.6V on excess current drawn and switch on Q2.I can add a transistor like Q2 in the + line to bias the Q2 if that can solve the problem
It's merely a Spice voltage source. You have nothing in your 'delay start orig.asc' circuit to raise the current through R3 to turn on Q2; so to get the effect of increasing the voltage drop across R3 I added V2 instead to turn on Q2. It's for simulation only, to test the delayed start of the 555; your real circuit won't need it.
Here's another modification, with hysteresis added to make the opamp snap-action. V2 is positioned differently but again simulates the voltage drop change across R3.
Edit: This asc file is wrong. Ignore it. See later post
I just placed an opamp and named it lm358 to show the spare opamp available.In a pnp transistor shouldnt the emitter be higher than the base and be connected to the plus and the base be connected after the 1E resistor? Can we connect the collector emitter of of a transistor directly across a capacitor to discharge it? wouldnt the discharge current be high enough to damage the transistor?
Can we connect the collector emitter of of a transistor directly across a capacitor to discharge it? wouldnt the discharge current be high enough to damage the transistor?