A digital pot was never intended to divide 5V down to 2.5 volts at 1% accuracy. In this case there are only 64 steps. About 78mV/step.
I have used digital pots to get the 2.5V at 1% another way.
Assume the 5V is +/-5%. (4.75 to 5.25V)
Using a divider set the top end of the pot to 2.7V and the bottom end to 2.3V. We don't know if he 5V is high or low but either way 2.5V is somewhere with the travel of the pot. Now we have 64 steps from 2.3 to 2.7V. About 6mV/step. There will be about 8 steps from -1% to +1% of the 2.5V. With a step of 6mV who cares if one step is 6mV and another is 7mV and another is 5mV you only need to get with in 25mV.
This is the same game we do with mechanical pots. To set a pot to 1% is not easy or repeatable. Most post have a end to end 20% or 30% and a linearity of 5%. But with the pot spanning from-7% to +7% it should be easy to hit with in 1%.
I have used digital pots to get the 2.5V at 1% another way.
Assume the 5V is +/-5%. (4.75 to 5.25V)
Using a divider set the top end of the pot to 2.7V and the bottom end to 2.3V. We don't know if he 5V is high or low but either way 2.5V is somewhere with the travel of the pot. Now we have 64 steps from 2.3 to 2.7V. About 6mV/step. There will be about 8 steps from -1% to +1% of the 2.5V. With a step of 6mV who cares if one step is 6mV and another is 7mV and another is 5mV you only need to get with in 25mV.
This is the same game we do with mechanical pots. To set a pot to 1% is not easy or repeatable. Most post have a end to end 20% or 30% and a linearity of 5%. But with the pot spanning from-7% to +7% it should be easy to hit with in 1%.