Easy. C programming question

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spitso

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Hi all

Just writing up some code, so far it all works perfectly until i accidentally enter a character (instead of an interger) for scanf.
It displays the menu over and over and over.....

Any ideas how i can get rid of this bug?
Im a beginner so i'd appreciate something as simplistic as possible.

Thankyou

attached is the code
 

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There is a function in C called " isadigit() " so first call scanf for a character "%c" then check if its a digit then convert to an int (atoi());

Code: 
char key;

if(isadigit(scanf("%c",key)))
   {
   process here;
   }
else
   dont;

something like this

Ian

OR.... just check that the scaned value is between 0 and 9.. (that's simpler)
 
Last edited:
The problem with "scanf" is that it leaves junk lying around in the buffer. If your menu is constantly being displayed, this might be the reason. Make a function like the one below, and call after the scanf line:

Code: 
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

...


void eat_junk(void) (
  int ch;

  while((ch = getchar()) != '\n') {
     if (ch < 0)
        exit(EXIT_FAILURE); //EOF!
  }
}

Find more information here : c - How to prevent the user from entering more data than the maximum limit? - Stack Overflow
 
thanks Ian

i tried checking the scanned value to see if its between 0 to 9, but if a character is press and it reloops.........its as if the programs skipping the scanf code and is just remembering what i had previously entered.

any ideas?
 
Thanks for that

Im guessing the " ( " after (void) is mean't to be " { ".

also sorry for a million question but as i said im a beginner.
What would be the code to call this function, so i can put it after my scanf() statement?

thanks in advance
 
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