Jeff, do you think Jaycar part RR0572 would do instead of the 2 470 resistors??
In Australia all electricians learn ohms law at TAFE (I am certain). This guy is pretty switched on. I asked him how I would test a wire to see if it would carry 3 amps. He said R=V/I so (if I'm reading his writing correctly), I would need to use a 36W resistor. But he said something about putting 5 20W's together instead. Maybe 4. Can't read the writing. I have no idea!!
Let me just go through the basics, and see if I understand it all. Sorry for my lack of knowledge here!!
As resistance goes up, current goes down. Hence the 10W resistor. It will drop the current below 3 Amps. Does this depend on something 'drawing' current?? There won't really be anything drawing current. As soon as 1 Amp flows through the ingightor, the circuit will be broken (as the ignightor fires).
The 2 470 Ohm (or 1 1K ohm) resistors are to protect the LEDs from excess current. They should drop the current to about 11 mA. Is that right?
I have put a 3 Amp fuse in the circuit. Now, I think the jey switch is rated at 3 Amps, so I guess I should drop the fuse to 2.5 Amps, so that the key switch won't blow first! But how do I know that there will not be more than that many amps normally, hence blowing the fuse all the time?? Because of the 10W fuse?
If the resistance of the ignighters varies between 1.8 and 2.2 ohms, this will be the equivalent of having a resistor there. If I have a 20M cable to get some distance between me and the fireworks, that will add to the resistance too. Will this be much? I guess it will depend on the cable used?
This is a lot more difficult than I thought!! I am beginning to think I might be better off just to spend the $2500 and buy a professional setup! But I want to avoid it if I can!
Thanks for your help guys!!