I guess you mean questions of the form:
No. I mean an "electronic engineer" that has to come here and ask questions about how to do design work. Work for a job and company he is already working for. Any more and we take it to PM.
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I guess you mean questions of the form:
Any more and we take it to PM.
Every time I hear, "a perfect call.", I think of Disney's, the goofy movie, and Goofy's "perfect cast" while teaching his sone how to go fly fishing. (I don't know why there is a John Cena commercial at the end of the video.it's not like it was some kind of a perfect call.
The one who always chooses air travel, but returns to the origin.No. I mean an "electronic engineer" that has to come here and ask questions about how to do design work. Work for a job and company he is already working for. Any more and we take it to PM.
I'm not seeing what the electrical design flaw might be. Just saying it is a common design error doesn't communicate enough information to make it true on its own. What is the error and what makes it a better design?
I just don't get it (the design issue) as currently explained.
I would agree that it's a design error to use a technique which is known to be unreliable in practice, but I think what everyone wants to know is 'WHY does it prove unreliable?'. My guess is that multiple resistors don't always share the load equally or are differently stressed. Tolerances, or adjacent stray capacitance or inductance might be a cause of that. Differences in thermal conditions might be a factor.
China will say "yes Vishay" but no then are not. Then China will say "very good resistor just like Vishay" but they are not.
The point here is not that two resistors are in series. It is that two resistors are in series where the voltage or power is too much for one resistor."This well-known problem has virtually no documentation on Internet forums... " - Honestly, just think how ridiculous this sounds.
Take for example a simple voltage divider with two resistors .... IN SERIES . Your telling me, that if I happen to NOT connect the center tap to anything in my circuit that one or both of the resistors in the divider will fail because they are connected in series? - That's essentially what everyone is claiming ... that's hog wash !!!
That is what designers commonly assume. But transients and stray capacitance can result in current differences, as the sim below demonstrates. C1 represents stray capacitance affecting primarily one of two series resistors.the current through each resistor is the same.
This well-known problem has virtually no documentation on Internet forums, manufacturers Application Notes, or manufacturers' datasheets for chip resistors (I've checked several). Can anyone point to any documentation on the subject?
Is it an electric power issue, a thermal/mechanical stress issue, or witchcraft issue?
edit: I used the word "virtually" in the first sentance because I did find this thread as the only source of info on series resistor failures smd. To be honest, I found nothing.
This well-known problem has virtually no documentation on Internet forums, manufacturers Application Notes, or manufacturers' datasheets for chip resistors .
"This well-known problem has virtually no documentation on Internet forums... " - Honestly, just think how ridiculous this sounds.
Take for example a simple voltage divider with two resistors .... IN SERIES . Your telling me, that if I happen to NOT connect the center tap to anything in my circuit that one or both of the resistors in the divider will fail because they are connected in series? - That's essentially what everyone is claiming ... that's hog wash !!!
I found MANY such examples of circuit failures in series resistors. I concede, however, that I do not have an MA in Journaling like you do, so I probably just don’t know how to use Google.