The attached drawing is exactly what I had, the switch was a mini clip and the load was a test light which draws about 150 ma. If you build the circuit using a 100 ohm resistor, and use an on/off switch or just touch wires together, you will prove a point, I don't know which point, but if the FET dies, that's one point, if the FET lives and works, that's the other point.
This is my guess as to what happens, with the switch open, a reverse charge builds up on the gate as shown in the attached drawing, maybe there should be a bunch more + in other areas, I DON'T KNOW, then when the switch is closed and the gate charge is drained off and the polarity of the gate charge is reversed, the fragile insulation is damaged because it happened so fast and the FET dies.
This is purely a guess, and I have only my own reasoning to pull from.
I don't want to throw challenges out, but if you are correct. building and trying the circuit can't hurt.
Kinarfi