M mgr1397 New Member Apr 1, 2012 #1 I'm wondering how iti s possible to find the maximum number of bjt current mirrors you can put together with an error that does not exceed 10% and β= 100.
I'm wondering how iti s possible to find the maximum number of bjt current mirrors you can put together with an error that does not exceed 10% and β= 100.
L lebevti Member Apr 6, 2012 #2 interesting question...isn't it where the more current mirrors u put in parallel, the less the error is? i would say 10% probably needs 1 or 2 max
interesting question...isn't it where the more current mirrors u put in parallel, the less the error is? i would say 10% probably needs 1 or 2 max
J Jony130 Active Member Apr 9, 2012 #3 The mathematical answer is 10.11 BJT's So I think that 10 is the answer Iref/Io = 1/ ( 1 + (1 + n)/β ) n - number of outputs Iref/Io = 1/ ( 1 + (1 + 10)/100 ) = 1/1.11 = 0.9009
The mathematical answer is 10.11 BJT's So I think that 10 is the answer Iref/Io = 1/ ( 1 + (1 + n)/β ) n - number of outputs Iref/Io = 1/ ( 1 + (1 + 10)/100 ) = 1/1.11 = 0.9009