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That won't work. What you are describing is an emitter follower. The emitter voltage will never get higher than 0.7V below the base, or about 3.9V, in this case.I'm not entirely sure about this, I honestly don't know enough about the practical circuits involved, but you may be able to get away with using a single NPN transistor. Feed the 4.6 volt signal into the base. Connect the collector to +12V and connect the emitter to the ECU input. Pretty much any NPN transistor will do.
I'm not entirely sure about this, I honestly don't know enough about the practical circuits involved, but you may be able to get away with using a single NPN transistor. Feed the 4.6 volt signal into the base. Connect the collector to +12V and connect the emitter to the ECU input. Pretty much any NPN transistor will do.
That's guaranteed smoke. You don't have any current limiting between the collector of the NPN and the base of the PNP.an emitter follower will only output the base voltage minus 0.6 or 0.7V, i.e. 4V
try something like this, no relays required..... just about any NPN and PNP transistor will do. the input resistor can be anything from 100 to 470 ohms, and the other two resistors can be anything from 1k to 10k.....