Ahh.. Let the AC capacitor do the heavy lifting then. Are you saying instead of my calculation above where I take the strings with a voltage drop of 74.8 (22leds) and 78.2 (23LEDs), I can shoot for Maybe 81 Volts instead of 100?
If I redid the calculation there 81Volts needed +6 for the bridge rectifer =87 V. 118 volts of the line make 31 volts I could drop at the capacitor.
31V/.1A = 310 ohms. C = 1/(2*pi*f*Xc) = 1/(2*3.14*60*310)=1.77e-5 =8.56 uF
On the AC side of the rectifier I would have a 8.56uf capacitor in parralel with the 1M ohm resistor.
Am I on the right track?
If I redid the calculation there 81Volts needed +6 for the bridge rectifer =87 V. 118 volts of the line make 31 volts I could drop at the capacitor.
31V/.1A = 310 ohms. C = 1/(2*pi*f*Xc) = 1/(2*3.14*60*310)=1.77e-5 =8.56 uF
On the AC side of the rectifier I would have a 8.56uf capacitor in parralel with the 1M ohm resistor.
Am I on the right track?