avenger09123
New Member
Alrighty so I'm starting to get tired of my 2.5 hours of battery life out of my desktop replacement and am looking to open up the battery and redo the cells myself. (yes I know its a desktop replacement, i'm just looking for something to do really).
I haven't opened it up yet but I'm going to I just wanted to do the math first see if it will be with buying higher capacity batteries and need my math checked
Battery info on the HP label is sit at 14.4v for 73,440 mWh (8 cells total)
Seeing as laptops today monitor more pairs of cells than individual or groups of 3 or more I can figure out that:
If my math is right then 73440mWh/14.4v gives me 5100mA for the entire 8 cell battery
2 cells in parallel give me 3.6v
x4 in series my bad I forgot to say in series.... for 14.4v @ 5100mA
so can I divide the 5100mA by 4 sets to get the mA of a set of 2 and then divide by 2 to get the capacity of one cell...right?
Is my math right? can anyone check this?
OK edited....should be correct now....
I haven't opened it up yet but I'm going to I just wanted to do the math first see if it will be with buying higher capacity batteries and need my math checked
Battery info on the HP label is sit at 14.4v for 73,440 mWh (8 cells total)
Seeing as laptops today monitor more pairs of cells than individual or groups of 3 or more I can figure out that:
If my math is right then 73440mWh/14.4v gives me 5100mA for the entire 8 cell battery
2 cells in parallel give me 3.6v
x4 in series my bad I forgot to say in series.... for 14.4v @ 5100mA
so can I divide the 5100mA by 4 sets to get the mA of a set of 2 and then divide by 2 to get the capacity of one cell...right?
Is my math right? can anyone check this?
OK edited....should be correct now....
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