nicksydney
New Member
Hi all,
I'm currently reading about Kirchhoff’s voltage law (KVL) and come to a brick wall in understanding something. One of the diagram that was shown was below with the explanation about it.
View attachment 61861
I understand that to calculate the KVL it is going clockwise from 12V all the way to Vo but what I'm confused about the following
(1) The equation in the diagram states
-12 + 4i + 2vo - 4 + 6i = 0
my question is since we are going clockwise why it is calculating +6i and not -6i because from my understanding the flow is going from 4V and entering the (-) polarity of the 6ohms ?
(2) The equation
Vo = -6i
How to derive that Vo is -6i and not +6i ?
Thanks for the help
I'm currently reading about Kirchhoff’s voltage law (KVL) and come to a brick wall in understanding something. One of the diagram that was shown was below with the explanation about it.
View attachment 61861
I understand that to calculate the KVL it is going clockwise from 12V all the way to Vo but what I'm confused about the following
(1) The equation in the diagram states
-12 + 4i + 2vo - 4 + 6i = 0
my question is since we are going clockwise why it is calculating +6i and not -6i because from my understanding the flow is going from 4V and entering the (-) polarity of the 6ohms ?
(2) The equation
Vo = -6i
How to derive that Vo is -6i and not +6i ?
Thanks for the help