I have a 2.5v vRef requirement and at first I looked to improve over a 2.5v zener using an LM4040-2.5. I then realised it has the same issue as a low voltage zener whereby a minimum current is required - and when the voltage rises this can become significant.
Which had me wondering if a LM4040 is nothing more than a trimmed zener?
Which brings me to the TL431. It requires 10% of the LM4040 current and is cheaper to purchase. The ATL431 uses 1% of the LM4040.
Am I missing a trick? Other than the TL431 only goes down to 0.5% accuracy vs 0.1% for the LM4040 I can't see any benefit?
If it is a zener, but it then it is more than just a trimmed zener. The construction would be different to get better noise and stability. So-called "buried zener". Sometimes also other stuff inside like temperature compensation.
The TI datasheet says it is a bandgap reference with compensation From general literature, it seems to be a more accurate than the typical bandgap reference but that could be due to the compensation.
It sounds like you're just driving from the supply via a resistor.
For better performance across supply voltage, you could consider driving your reference from a current source.
It sounds like you're just driving from the supply via a resistor.
For better performance across supply voltage, you could consider driving your reference from a current source.
If I understand correctly, they still have some dependence on current - but I was mainly thinking of reducing dissipation, which would depend on V, rather than V^2.
Well you certainly could use a voltage regulator plus resistor to set the current, but hat I had in mind was something like this:
(just a picture from the net... obviously you'd put the zener/shunt reference where the LEDs are). I believe it's quite a common technique for getting the best performance from shunt regulators, and particularly from zeners.
On the other hand, I may have misinterpreted your problem. I'd assumed you where saying that with a resistor sized to meet the regulator's minimum current requirement at the minimum supply voltage, you ended up with excessive current at the maximum supply voltage. "Excessive" could mean several things; exceeding the regulator's maximum current, drawing too much from your supply (maybe it's a battery, etc) or dissipating an uncomfortable amount of power in the resistor. In that case, this kind of circuit helps as the current is more-or-less independent of the supply voltage.
Sorry I couldn't elaborate more yesterday - I was a bit pressed for time.
That was my problem but I'd read the datasheet incorrectly. Indeed the LM4040-2.5 needs minimal cathode current to operate so 4-30V with a 40k resistor is possible. So all sorted!