ccurtis
Well-Known Member
I got it to where I am quite satisfied now. Ear hears voltage, S, as S^0.3. Eye sees voltage ,S, as S^0.5. Take the square root of the voltage, S^0.5, and call it S'. Eye sees S' as S'^0.5=S^0.25 which is close to S^0.3, which is what the ear hears. Experiment with that approach looks quite right.