Follow along with the video below to see how to install our site as a web app on your home screen.
Note: This feature may not be available in some browsers.
A 12 V battery will need 50A to reach 20V.
1) The panel can not make that much power.
2) This will result in the battery boiling over and exploding.
Q2. There's no voltage drop. If you connect panel directly to the battery, they, obviously, will be at the same voltage. The problem is that you could've used 20V and would get nearly the same current from the panel. But you used 14V, so you unrealized (8x20) - (8-14) = 48W.
You can't connect a 20V 8A panel direct to the battery. The battery could explode without a charge controller.
Thank you, KISS, ronsimpson, NG, MrAl, for your help.
Q1:
Do you mean to say that a 12 V battery would need 50 A of current to reach 20 V if it was directly connected to 20 V panel which can only supply 8 A of current.
Could someone please help me with Q2 and Q3?
Please try to keep it simple because I need to understand all this soon. Thanks a lot.
Regards
PG
One very simplified view would be a current source in parallel with a resistance. When we draw no current from it the voltage is maximum because V=I*R and I is constant and R is constant, so V comes from those two, and the voltage here is the open circuit voltage. When we connect a load however even if that load is a battery, that draws some current and so the equation now looks more like this:
V=(I-iLoad)*R