What confused me is that you drew the FET upside-down from how it's usually shown on a schematic (drain on top). So you do have a negative voltage on the drain as needed. Drawing circuits in a unconventional manner, makes it more difficult to analyze. That may be why you made the drain resistor smaller than the source resistor, which is opposite of the typical circuit.
You equation is correct. But it means Vs must be less (more negative) the Vg.
What confused me is that you drew the FET upside-down from how it's usually shown on a schematic (drain on top). So you do have a negative voltage on the drain as needed. Drawing circuits in a unconventional manner, makes it more difficult to analyze. That may be why you made the drain resistor smaller than the source resistor, which is opposite of the typical circuit.
You equation is correct. But it means Vs must be less (more negative) the Vg.
So in the end what i did for Vd was play around with the resistor value until i got an output. Not very technical but it worked.
Can you help me witht the equation for Vd, seeing though Rd has -12v on one side of it i used this calculation to find Rd, but it didnt really work. Rd 3k seems to work good.
Vd,max= Vg + |Vp| (to keep FET in saturation)
so Vd,max= 4.94 + 2.7 = 7.64
Rd = [7.64 - (-12)]/1mA = 19640 ohms. But that didn't work.
And also Rd being 3k would that give a Vd of (3k * 1mA)-(-12) = 9v?