Boncuk
New Member
Pressure differential LED project
Hi tsneidin,
you've got a point here. Better make a new thread about pilots, those of them who never were pilots and model aircraft pilots.
Here is a suggestion: If your reference pressure has a constant value you won't need a pressure sensor there. The transducers you have selected have an output range of 1 to 6V. That has to be reduced to 0 to 5V in order to control the LM3914 circuit properly. Use a difference amplifier to achieve that.
Use another difference amplifier to compare the measured pressure value with the reference pressure which should equal 5V. The higher the voltage difference the more LEDs will be lit. Check the schematic. It contains the difference amplifier and the appropriate LM3914 circuit to illuminate 10 LEDs at full difference and none at zero difference.
You can use a TLC271 instead of an LM324. That's one the simulation works with. Notice the voltage difference. There is an input voltage of 4.49V resulting in an output voltage of 0.51V. 0.5V is the minimum voltage to have the first LED illuminated (5V/10LEDs=0.5V per LED)
Regards
Boncuk
Edit: Don't forget current limiting resistors for the LEDs. Omitted for simulation purposes. The monitor doesn't fry because of that. RV=VDD-Vf/If (R(Ohm)=VDD(V)-Vf(V)/If(A))
Hi tsneidin,
you've got a point here. Better make a new thread about pilots, those of them who never were pilots and model aircraft pilots.
Here is a suggestion: If your reference pressure has a constant value you won't need a pressure sensor there. The transducers you have selected have an output range of 1 to 6V. That has to be reduced to 0 to 5V in order to control the LM3914 circuit properly. Use a difference amplifier to achieve that.
Use another difference amplifier to compare the measured pressure value with the reference pressure which should equal 5V. The higher the voltage difference the more LEDs will be lit. Check the schematic. It contains the difference amplifier and the appropriate LM3914 circuit to illuminate 10 LEDs at full difference and none at zero difference.
You can use a TLC271 instead of an LM324. That's one the simulation works with. Notice the voltage difference. There is an input voltage of 4.49V resulting in an output voltage of 0.51V. 0.5V is the minimum voltage to have the first LED illuminated (5V/10LEDs=0.5V per LED)
Regards
Boncuk
Edit: Don't forget current limiting resistors for the LEDs. Omitted for simulation purposes. The monitor doesn't fry because of that. RV=VDD-Vf/If (R(Ohm)=VDD(V)-Vf(V)/If(A))
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