vinodquilon Member Mar 4, 2013 #1 Resistance/Voltage measurement using multimeter Consider the below circuit with 28V supply and 5A load. What voltage would I expect when I connect a multimeter between A & B ? V(AB1)= V(R6)+V(R8)+V(R9) What voltage would I expect when I connect a multimeter between C & D ? V(CD1)= V(R7)+V(R8)+V(R10) Consider the second circuit. What voltage would I expect when I connect a multimeter between A & B ? V(AB2)= V(R6)+V(R8)+V(R9) What voltage would I expect when I connect a multimeter between C & D ? V(CD2)= V(R8) Am I right ? And V(AB2)>V(AB1) Attachments Rsistance.jpg 59.9 KB · Views: 185 Last edited: Mar 4, 2013
Resistance/Voltage measurement using multimeter Consider the below circuit with 28V supply and 5A load. What voltage would I expect when I connect a multimeter between A & B ? V(AB1)= V(R6)+V(R8)+V(R9) What voltage would I expect when I connect a multimeter between C & D ? V(CD1)= V(R7)+V(R8)+V(R10) Consider the second circuit. What voltage would I expect when I connect a multimeter between A & B ? V(AB2)= V(R6)+V(R8)+V(R9) What voltage would I expect when I connect a multimeter between C & D ? V(CD2)= V(R8) Am I right ? And V(AB2)>V(AB1)
JimB Super Moderator Most Helpful Member Mar 4, 2013 #2 Am I right ? Click to expand... Yes. Assuming that the impedance of the voltmeter is high compared with the values of the resistors. And V(AB2)>V(AB1) Click to expand... Yes, if the load current is the same 5 amp. JimB Last edited: Mar 4, 2013
Am I right ? Click to expand... Yes. Assuming that the impedance of the voltmeter is high compared with the values of the resistors. And V(AB2)>V(AB1) Click to expand... Yes, if the load current is the same 5 amp. JimB
vinodquilon Member Mar 4, 2013 #3 JimB said: Yes. Assuming that the impedance of the voltmeter is high compared with the values of the resistors. Yes, if the load current is the same 5 amp. JimB Click to expand... It is an electronic load set at 5A Constant Current mode.
JimB said: Yes. Assuming that the impedance of the voltmeter is high compared with the values of the resistors. Yes, if the load current is the same 5 amp. JimB Click to expand... It is an electronic load set at 5A Constant Current mode.
C canadaelk Active Member Mar 4, 2013 #4 Without resistor values you are wasting time and effort. The rest, once R values are given, is grade 5 arithmatic. E
Without resistor values you are wasting time and effort. The rest, once R values are given, is grade 5 arithmatic. E
vinodquilon Member Mar 4, 2013 #5 canadaelk said: Without resistor values you are wasting time and effort. The rest, once R values are given, is grade 5 arithmatic. E Click to expand... Sorry, It is intended for voltage measurement not resistance.
canadaelk said: Without resistor values you are wasting time and effort. The rest, once R values are given, is grade 5 arithmatic. E Click to expand... Sorry, It is intended for voltage measurement not resistance.
JimB Super Moderator Most Helpful Member Mar 4, 2013 #6 Without resistor values you are wasting time and effort. Click to expand... That was my initial reaction, until I read the question a second time. As VQs question is written, you do not need to know the resistance values. JimB
Without resistor values you are wasting time and effort. Click to expand... That was my initial reaction, until I read the question a second time. As VQs question is written, you do not need to know the resistance values. JimB
JimB Super Moderator Most Helpful Member Mar 4, 2013 #7 The question as written is vague and confusing, it would be much better if the thread title was simply: Voltage measurement And the words What would I expect when I connect a multimeter between A & B ? Click to expand... What voltage would I measure between A and B? Only when you read the expression: V(AB1)= V(R6)+V(R8)+V(R9) Click to expand... does it become clear what the real question is. JimB
The question as written is vague and confusing, it would be much better if the thread title was simply: Voltage measurement And the words What would I expect when I connect a multimeter between A & B ? Click to expand... What voltage would I measure between A and B? Only when you read the expression: V(AB1)= V(R6)+V(R8)+V(R9) Click to expand... does it become clear what the real question is. JimB