The relay was designed to have its current limited by the inductance, not its resistance. When the relay is open, its inductance is small, so it takes more power, which is normal, but only lasts for a short time, so doesn't overheat the relay.
Could you please elaborate a bit?
Thanks a lot.
Have a look at the specification for this relay:-
https://docs-emea.rs-online.com/webdocs/1582/0900766b81582926.pdf
It says:-
Coil Power: 2VA
Coil Resistance: 8200 Ω
Coil Voltage: 230V ac
2 VA at 230 V is about 8.7 mA.
230 V across 8200 Ω is about 28 mA
The difference is caused by the inductance of the coil.
The coil's inductance will be much less when the coil is not energised, because the magnetic circuit is not fully closed.
On a contactor, the specification is clearer.
https://docs-emea.rs-online.com/webdocs/13df/0900766b813df0b7.pdf
It says:-
Inrush power in VA 70 VA at 20 °C (cos ϕ 0.75) 50 Hz
Hold-in power consumption in VA 7 VA at 20 °C (cos ϕ 0.3) 50 Hz
So the current consumption is 10 times as much at inrush. When the contactor is energised, the inductance is much more, which is why the current is much less and the power factors is so low.