A anampiracha New Member Nov 30, 2011 #41 I got p1 = -A/2 + (1/2)sqrt(A^2-4B) and p2= -A/2 - (1/2)sqrt(A^2-4B) .. roots So should I put it like D/ (s-p1)(s-p2) ???
I got p1 = -A/2 + (1/2)sqrt(A^2-4B) and p2= -A/2 - (1/2)sqrt(A^2-4B) .. roots So should I put it like D/ (s-p1)(s-p2) ???
M MrAl Well-Known Member Most Helpful Member Dec 1, 2011 #43 Hi, When you factor s^2+A*s+B you get two roots, r1 and r2. To get that second degree expression back again you have to multiply (s-r1)*(s-r2). Example: s^2+5*s+6 roots: r1=-2, r2=-3 The factorization is (s-r1)*(s-r2) so we get (s-(-2))*(s-(-3))=(s+2)*(s+3) Last edited: Dec 1, 2011
Hi, When you factor s^2+A*s+B you get two roots, r1 and r2. To get that second degree expression back again you have to multiply (s-r1)*(s-r2). Example: s^2+5*s+6 roots: r1=-2, r2=-3 The factorization is (s-r1)*(s-r2) so we get (s-(-2))*(s-(-3))=(s+2)*(s+3)