SCALING OF VOLTAGE

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A simple voltage divider using two resistors, is an easy way to do it.

JimB
 
paridhi jain said:
how to scale the 9V to 660mV.
Click to expand...
paridhi jain said:
yes, i m using voltage divider my resistor burn.
Click to expand...
paridhi jain said:
r2/r1 = 12/1
I take the output form r2
Click to expand...

Instead of these simple one line statements, why don't you tell us what you are trying to do?

Where does the 9volts come from?
Where does the 660mV go to?
Your resistors burned? what value (ohms) were your resistors?

The more information you give to us, the better we can help you.

JimB
 
Your power supply is 9V and your voltage divider produces 660mV. Then if the lower resistor is a 1/4W one it will burn if its current is 0.25W/0.66V= 379mA or more and if its value is 0.66V/379mA= 1.74 ohms or less.
The upper resistor will have 9V - 0.66V= 8.34V across it and its heating is 8.34V x 379mA= 3.16W. Its value is 8.34V/379mA= 22 ohms.

Why are your resistor values so low causing the current and heating to be so high?? Use a 1.74k resistor for the lower one and a 22k resistor for the upper one and they will stay cold.
 
paridhi jain said:
how to scale the 9V to 660mV.
Click to expand...
I don't why you want to get 0.660 volts.
If you need 0.66 volts to run a motor then that is a very different thing.
If you need 0.66 volts to drive a small meter then that is another thing.

More information please.
 
Is 0.66V the base-emitter voltage of your transistor or forward voltage of your diode?
 
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