If R9 is missing, it will have the same effect as it having a high value, so the voltage on it will go up. If you want to sense that as being a different condition, you need a separate comparator. The separate comparator would have a different threshold set by another voltage divider.
I've got a couple of comments about the circuit. If you want this circuit to work in real life, your resistors values are too high for the op-amp input. 100 MΩ is going to get swamped by leakage currents. I would suggest staying below 100 kΩ unless you look carefully at leakage.
You've not got enough current driving the base of the transistor. The 120 kΩ resistor gives you 100 μA. The transistor gain is only guaranteed to be 100 at 10 mA, and less at the 25 mA that you are running, so you need at least 250 μA for reliable operation. Also, even 100 μA through the LED could make it glow, so you should put maybe 2.2 kΩ in parallel.
I can't see why you are using the transistor at all. You could just have the the green LED and its resistor connected between the comparator output and ground.
Can you explain what the circuit does? If R9 is just a resistor, the circuit will never switch, so what is R9 in your application?