ok, so what is the formula for correct wattage? and is there any way to add thermal compensation, or this too complex? i read somewhere about adding silicon diodes from transistors base to ground, but i dont want to fry anything from uncorrect tweaking
and, you said not 4ohm loads, welll i used 4ohm speakers, not surprise then it burned....
The formula is pretty simple - W=V*V/R
R is simply the speaker impedance, the trick is to find V.
You said 46V on each capacitor?, so assuming this means a +/-46V supply, this gives a 92V supply rail (off load).
First assumption - the rails
will drop under load (plus losses in the amplifier), so assume a 'rough' maximum peak to peak output voltage of 80V.
Convert p-p to RMS - 80/2.828 = 28V RMS
28 * 28 = 784 (V squared)
Now simply divide by the speaker impedance
784/4 = 196W (4 ohm load)
784/8 = 98W (8 ohm load)
Assuming the 46V is the total supply rail, those powers reduce by a factor of four, giving 49W to 4 ohms, and 24.5W to 8 ohms.
This last figures seem just about plausible for TIP41/42 (although 4 ohms is probably pushing things a bit), the first calculations (92V total supply) is massively beyond their capabilities, unless they are just drivers feeding some much more substantial output transistors.