Hero999
Banned
No that's a worst case scenario when driving a load of 200mA.The max output high voltage of the 555 is only 4V and the minimum voltage is 2V.
With only 2V across it an 8 ohm speaker gets only 125mW for a sine-wave or only 0.25W for a square-wave.
In reality the saturation voltage won't as high. The load seen by the 555 will be the beta of the transistors multiplied by the emitter load.
No, I was talking about the single ended driver I posted previously.For 2.25W an 8 ohm speaker needs 12V p-p and a 555 cannot supply enough current. The amplifier needs a 14V to 16V supply.
https://www.electro-tech-online.com/attachments/tone-gen-gif.32336/
The saturation voltage of the transistor is negligible, if the P = 6²/8 = 4.5W but the duty cycle will be about 50% so that becomes 2.25W like I said.
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