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catcat said:How big of an inductor you will need?
The 2200uF filter cap and the LM317 voltage regulator will reduce the ripple voltage so low that it cannot be measured, if a 10uF cap is connected to the ADJ pin of the LM317 to ground.catcat said:the inductors are correct, they are to smooth the ripple voltage from the capacitor.
Then when the load is disconnected the regulated output voltage will rise.nikhil arora said:one more thing i have used 330 ohm as R1 instead of 240 ohm i think this wont be a problem
Or at very high currents and then there's also voltage drop as they smooth out the current ripple, not to mention the voltage spike they produce when you remove the load.Nigel Goodwin said:At 50/60Hz the inductors would need to be huge to do anything, so it's extremely rare to have inductors like that. Where you do get them is in switch-mode supplies, where the high frequency used makes them worthwhile.
The output voltage from the regulator will rise when there isn't a load.nikhil arora said:so what is the overall effect in using 330ohm instead of 240ohm
Even ON Semi and Texas Instruments got it wrong on their copy of National Semi's LM317. I believe in National Semi because they invented the LM317.AllVol said:Who do we believe?
You still need to calculate the value of the other resistor which is about half of its value when using 240 ohms.nikhil arora said:i got it guru so we will use 120 ohms from now cause i am using lm317 from ST.
i belive more in forum then in datasheet