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Transistor o/p voltage swing

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walid66

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I have thought long about voltage swing
In order the swing to be symetrical, Which is correct: (when there is an unbypassed Emitter resistor)
VC = 0.5 VCC OR VCE =0.5 VCC
in another way: The o/p ac signal is being mounted on the VC dc voltage or on VCE dc voltage?
thanks alot
 
Last edited:
I have thought long about voltage swing
In order the swing to be symetrical, Which is correct: (when there is an unbypassed Emitter resistor)
VC = 0.5 VCC OR VCE =0.5 VCC
in another way: The o/p ac signal is being mounted on the VC dc voltage or on VCE dc voltage?
thanks alot

hi,
Look here:
**broken link removed**

also Google for Class A Amplifiers
 
hi,
Look here:
**broken link removed**

also Google for Class A Amplifiers

Thank you ericgibbs for the quick response
I have my university book in electronics, I want to discuss some of the concepts here
I write a design file using MATHCAD for fixed bias emitter-stabilized transistor circuit. In text book, for symetrical o/p VCE must equals half of power supply (VCC)
I think that VC not VCE must = 0.5 VCC, cause ac o/p is on VC dc at the collector and not on VCE.
 
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