zipdogso: I'm not sure. Hence, the multimeter and my apparent ADD. I am certain I accidentally shorted the probes on the multimeter yesterday when I had it dialed to temperature so I'm back to presuming this is a diode.
I've back-tracked a little lately as I'm getting more details about how I can use this thing. I took the bigger multimeter home last night and took a reading at room temperature (25*C) then from the freezer later (-20*C) and from the fridge this morning (3*C). I jotted them down on some paper on my desk at home so I don't have them just yet. But, iirc, I got .0019V/*C.
Right now I'm trying to figure out how exactly to use the comparator. With a diode the voltage drop is the difference in voltage from either side of it, correct? If I apply 24V to the diode and it has a .66V drop then does the wire past the diode only have 23.34V? Does the voltage drop change with the amount of voltage applied? If all this is correct then what do you use for a reference voltage? If the voltage drop decreases with an increase in temperature, then the voltage past the diode will increase with an increase in temperature? Thus, from what I can tell, I would need a reference voltage such that when the voltage past the diode is greater than the reference voltage then the the comparator passes electricity. The only thing I can think of is building a circuit just for reference voltage.
I've back-tracked a little lately as I'm getting more details about how I can use this thing. I took the bigger multimeter home last night and took a reading at room temperature (25*C) then from the freezer later (-20*C) and from the fridge this morning (3*C). I jotted them down on some paper on my desk at home so I don't have them just yet. But, iirc, I got .0019V/*C.
Right now I'm trying to figure out how exactly to use the comparator. With a diode the voltage drop is the difference in voltage from either side of it, correct? If I apply 24V to the diode and it has a .66V drop then does the wire past the diode only have 23.34V? Does the voltage drop change with the amount of voltage applied? If all this is correct then what do you use for a reference voltage? If the voltage drop decreases with an increase in temperature, then the voltage past the diode will increase with an increase in temperature? Thus, from what I can tell, I would need a reference voltage such that when the voltage past the diode is greater than the reference voltage then the the comparator passes electricity. The only thing I can think of is building a circuit just for reference voltage.