I say that the circuit is "tricky", as in, there are several things which don't make sense.
The transistor is drawn as a PNP type.
A PNP transistor has the emitter connected to the +ve side of the supply and the collector to the -ve side.
The "supply" is drawn as a battery (a single cell actually), the long stroke of the battery symbol is usually the +ve side.
But here we have the +ve side connected to the collector and the -ve side connected to the emitter.
This is the wrong way around for the PNP transistor.
We are told that Icq is 3mA, I assume this means the quiescent collector current is 3mA.
I assume that the transistor has high gain so the base current is very small compared with the collector current, so we can say that the emitter current = collector current = 3mA.
We can calculate the voltage across the emitter resistor using V = I x R
so
V = 3ma X 500 Ohm = 1.5 volts.
We can calculate the base voltage, measured with respect to the common point of the circuit (the earth symbol).
So,
Base Voltage = Emitter voltage + Emitter- Base voltage
For a silicon transistor, base-emitter voltage will be about 0.5 to 0.6 volts when the transistor is biased into conduction, so we have:
Base voltage = 1.5v + 0.5v = 2.0 volts. (Negative with respect to the common point).
Looking at the circuit in the question, the base voltage is shown as -8volts (with respect to the common point.
So what is it 2v or 8v on the base?
Damned if I know!
As I have been typing, LvW has described the circuit as "Crazy", I think that he is correct.
JimB